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CGP EDU Academic Team
Published on: September 12, 2026
The coefficient of thermal conductivity of copper is nine times that of steel. In the composite cylindrical bar shown in the figure. What will be the temperature at the junction of copper and steel
Text Solution
Verified by ExpertsThe correct answer is:
A
Temperature of interface $\theta = \frac{K_1 \theta_1 l_2 + K_2 \theta_2 l_1}{K_1 l_2 + K_2 l_1}$ It is given that $K_{Cu} = 9K_s$. So if $K_s = K_1 = K$ then $K_{Cu} = K_2 = 9K$ $\Rightarrow \theta = \frac{9K \times 100 \times 6 + K \times 0 \times 18}{9K \times 6 + K \times 18} = \frac{5400K}{72K} = 75^\circ C$
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